LED Light Wiring
From what I'm understand, there is no voltage drop through long wiring for led.
Does anyone know if that means led lighting uses only one gage of wire - no
matter how long the run?
That would result in huge savings over traditional kits, since it's
the wiring that starts to get expensive because longer runs require
more-expensive, heavier-gage wire.
Comments
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Dude, I need to thanks you
Dude, I need to thanks you first. I wished to have wiring for my new house but I was confused. Your article helped me a lot.
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Voltage drop isnt going to be a probelm
Voltage drop isn't going to be a problem at all unless you are doing over 20-30 fixtures on one home run on 12/2 wire. I wouldn't worry about it!
John Paul Cambruzzi
www.ledlandscape.org
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Mike's comments are solid;
Mike's comments are solid; not meaning to contradict at all here ... low wattage at a given voltage means low current, that's the P = E*I (power is voltage time amperage "E" for "electro-motive force" ... dunno why current is "I").
But just to clarify on the nuts&bolts: the reason long-distance transmission lines are high-voltage is that there's less loss. But unless you're using a really small guage (with a "u", right? *grin*) that shouldn't be a concern. Anyhow, for reliability I don't imagine anyone using fine wire.
And concerning DC VS AC, history holds the a tale of nasty marketing and competition, but fact is /with higher voltages/ DC is to be avoided; it causes muscles to clamp down, whereas AC causes a twitch which is more likely to push someone clear of the shock source. (I got hit by 700B+ DC working on a transmitter; I didn't die but it isn't something I'm likely to forget. Quite a different kettle of fish!)
--bentrem
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Brad, The voltage drop is a
Brad,
The voltage drop is a product of the total wattage of the lights on that wire, the size of the wire, and the length of the wire. Since LED's us 1/5th the energy of a Halogen, you will be able to have longer runs with the same gauge wire.